2x^2-73x+288=0

Solution for 2x^2-73x+288=0 equation:

2x^2-73x+288=0

a = 2; b = -73; c = +288;
Δ = b2-4ac
Δ = -732-4·2·288
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-55}{2*2}=\frac{18}{4}
=4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+55}{2*2}=\frac{128}{4}
=32
$